Convert from type X to type YTag(s): String/Number
integer to String :
int i = 42; String str = Integer.toString(i); or String str = "" + i
String str = Double.toString(i);
String str = Long.toString(l);
String str = Float.toString(f);
String to integer :
str = "25"; int i = Integer.valueOf(str).intValue(); or int i = Integer.parseInt(str);
Double d = Double.valueOf(str).doubleValue();
long l = Long.valueOf(str).longValue(); or Long l = Long.parseLong(str);
Float f = Float.valueOf(str).floatValue();
int i = 42; String bin = Integer.toBinaryString(i);
   int i = 42;
   String hexstr = Integer.toString(i, 16);
   or
   String hexstr = Integer.toHexString(i);
   or (with leading zeroes and uppercase)
   public class Hex {
     public static void main(String args[]){
       int i = 42;
       System.out.print
         (Integer.toHexString( 0x10000 | i).substring(1).toUpperCase());
     }
   }
See this How-to
hexadecimal (String) to integer :
int i = Integer.valueOf("B8DA3", 16).intValue();
   or
int i = Integer.parseInt("B8DA3", 16);     
String s = String.valueOf('c');
char c = 'A'; int i = (int) c; // i == 65 DECIMAL
String test = "ABCD";
for ( int i = 0; i < test.length(); ++i ) {
   char c = test.charAt( i );
   int j = (int) c;
   System.out.println(j);
}b = (i != 0); // ex : 42 != 0 --> true
i = (b)?1:0; // true --> 1
try{
  i = Integer.parseInt(aString);
}
catch(NumberFormatException e) {
  ...
}
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