Convert from type X to type YTag(s): String/Number
integer to String :
int i = 42; String str = Integer.toString(i); or String str = "" + i
String str = Double.toString(i);
String str = Long.toString(l);
String str = Float.toString(f);
String to integer :
str = "25"; int i = Integer.valueOf(str).intValue(); or int i = Integer.parseInt(str);
Double d = Double.valueOf(str).doubleValue();
long l = Long.valueOf(str).longValue(); or Long l = Long.parseLong(str);
Float f = Float.valueOf(str).floatValue();
int i = 42; String bin = Integer.toBinaryString(i);
int i = 42; String hexstr = Integer.toString(i, 16); or String hexstr = Integer.toHexString(i); or (with leading zeroes and uppercase) public class Hex { public static void main(String args[]){ int i = 42; System.out.print (Integer.toHexString( 0x10000 | i).substring(1).toUpperCase()); } }
See this How-to
hexadecimal (String) to integer :
int i = Integer.valueOf("B8DA3", 16).intValue(); or int i = Integer.parseInt("B8DA3", 16);
String s = String.valueOf('c');
char c = 'A'; int i = (int) c; // i == 65 DECIMAL
String test = "ABCD"; for ( int i = 0; i < test.length(); ++i ) { char c = test.charAt( i ); int j = (int) c; System.out.println(j); }
b = (i != 0); // ex : 42 != 0 --> true
i = (b)?1:0; // true --> 1
try{ i = Integer.parseInt(aString); } catch(NumberFormatException e) { ... }